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6.x^2+2.x-8.4=0
a = 6.; b = 2.; c = -8.4;
Δ = b2-4ac
Δ = 2.2-4·6.·(-8.4)
Δ = 205.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.)-\sqrt{205.6}}{2*6.}=\frac{-2-\sqrt{205.6}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.)+\sqrt{205.6}}{2*6.}=\frac{-2+\sqrt{205.6}}{12} $
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